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Yahoo!奇摩知識+ - 分類問答 - 電腦網路 - 已解決 
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C語言 直式乘法
Dec 2nd 2013, 20:41

// 程式開始
#include "stdio.h"
#include "conio.h"

void main()
{
    unsigned int a, b, c, d;
    double check;
    int i, input_ok = 0;

    while (!input_ok) {
        printf("請輸入被乘數: "); scanf("%u", &a);
        printf("請輸入  乘數: "); scanf("%u", &b);
        check = (double)a*b;
        if (check <0 || check > 4294967295L) {
            printf("乘積必須介於0 ~ 4294967295之間\n\n");
        }
        else
            input_ok = 1;
    }
    printf("\n%22u\n", a);
    printf("x%21u\n", b);
    printf("----------------------\n");
    for (c=b, i=0; c>0; c=c/10, i++) {
        d = c%10;
        printf("%*u\n", 22-i, d*a);
    }
    printf("----------------------\n");
    printf("%22u\n", a*b);
    _getch();
}
// 程式結束

執行結果:
請輸入被乘數: 1546
請輸入  乘數: 6879

                  1546
x                 6879
----------------------
                 13914
                10822
               12368
               9276
----------------------
              10634934

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